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질문

안녕하세요 저는 팀용 앱을 개발하고 싶지만이 오류가 발생합니다.

java.net.SocketException: Address family not supported by protocol family: connect
    at java.net.DualStackPlainSocketImpl.connect0(Native Method)
    at java.net.DualStackPlainSocketImpl.socketConnect(DualStackPlainSocketImpl.java:79)
    at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:350)
    at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:206)
    at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:188)
    at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:172)
    at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:392)
    at java.net.Socket.connect(Socket.java:606)
    at java.net.Socket.connect(Socket.java:555)
    at sun.net.NetworkClient.doConnect(NetworkClient.java:180)
    at sun.net.www.http.HttpClient.openServer(HttpClient.java:463)
    at sun.net.www.http.HttpClient.openServer(HttpClient.java:558)
    at sun.net.www.http.HttpClient.<init>(HttpClient.java:242)
    at sun.net.www.http.HttpClient.New(HttpClient.java:339)
    at sun.net.www.http.HttpClient.New(HttpClient.java:357)
    at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(HttpURLConnection.java:1226)
    at sun.net.www.protocol.http.HttpURLConnection.plainConnect0(HttpURLConnection.java:1162)
    at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:1056)
    at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:990)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1570)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1498)
    at java.net.URL.openStream(URL.java:1067)
    at de.tbprivi.mgde.Home.Home.getEventData(Home.java:37)
    at de.tbprivi.mgde.Home.Home.<init>(Home.java:29)
    at de.tbprivi.mgde.main.Main.main(Main.java:8)

내 코드는 다음과 같습니다.

package de.tbprivi.mgde.Home;

import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

import javax.swing.*;
import java.awt.*;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.MalformedURLException;
import java.net.URL;

public class Home {

 public JFrame frame;
 private JSONParser parser;

 public Home(){

    frame = new JFrame();
    frame.setTitle("Miners-Games.de - TEAM APP");
    frame.setSize(700,500);
    frame.setVisible(true);
    frame.setLocationRelativeTo(null);

    try {
        getEventData();
    } catch (IOException | ParseException e) {
        e.printStackTrace();
    }

 }
 private void getEventData() throws IOException, ParseException {

    Object obj = parser.parse(new InputStreamReader(new URL("http://mylink.com/events.json").openStream()));

    JSONObject file = (JSONObject) obj;

    file.get("events");

  }
}

org.json.simple 라이브러리를 사용하고 있습니다.

문제 는 작동하는 것보다  공개 정적 void main () 에서 Home home = new Home ()이 아닌 getEventsdata ()를 호출 하는 것입니다.

도움을 주셔서 미리 감사드립니다 :)

 

답변1

이것은 호출이 IPv4 스택을 사용하지 않는 경우 발생합니다.

Java 옵션-Djava.net.preferIPv4Stack = true 가 트릭을 수행 할 것이라고 생각합니다.

이클립스를 사용하는 경우 jvm 프로그램 라인 인수를 통해 설정하십시오.



 

 

 

 

출처 : https://stackoverflow.com/questions/63209653/getting-java-socketexception

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